Loading Java Properties Files

Java Properties files are amazing resources to add information in Java. Generally these files are used to store static information in key and value pair. Things that you do not want to hard code in your Java code goes into properties files. Although there are multiple ways of loading properties file, I will be focusing on loading the resource bundle files from class path resources. There are advantages of adding properties files in the classpath:
  1. The properties files became a part of the deployable code (e.g. JAR file) making it easy to manage.
  2. Properties files can be loaded independent of the path of source code.
Let us see the simple way of Loading a property file in Java code. There are two ways of loading properties files in Java. 1. Using ClassLoader.getResourceAsStream() 2. Using Class.getResourceAsStream() In our example we will use both methods to load a properties file. Following is the content of sample properties file. The properties file will be in package net.viralpatel.resources. net/viralpatel/resources/config.properties
hello.world=Hello World
Code language: Java (java)
To load properties file using Classloader, use following code:
this.getClass() .getResourceAsStream("/some/package/config.properties");
Code language: Java (java)
The Class.getResourceAsStream(name) returns an Inputstream for a resource with a given name or null if no resource with the given name is found. The name of a resource is a ‘/’-seperated path name that identifies the resource. If the name with a leading “/” indicates the absolute name of the resource is the portion of the name following the ‘/’. In Class.getResourceAsStream(name), the rules for searching resources associated with a given class are implemented by the defining class loader of the class. This method delegates to this object’s class loader. If this object was loaded by the bootstrap class loader, the method delegates to ClassLoader.getSystemResourceAsStream(java.lang.String). So in our example to load config.properties we will have a method loadProps1().
private Properties configProp = new Properties(); ... public void loadProps1() { InputStream in = this.getClass().getResourceAsStream("/net/viralpatel/resources/config.properties"); try { configProp.load(in); } catch (IOException e) { e.printStackTrace(); } }
Code language: Java (java)
To load properties file using Classloader, use following code:
this.getClass() .getClassLoader() .getResourceAsStream("some/package/config.properties");
Code language: Java (java)
The ClassLoader.getResourceAsStream(name) returns an Inputstream for reading the specified resource or null if the resource could not be found. The name of a resource is a ‘/’-seperated path name that identifies the resource. The name no leading ‘/’ (all namea are absolute). So in our example to load config.properties we will have a method loadProps2().
private Properties configProp = new Properties(); public void loadProps2() { InputStream in = this.getClass().getClassLoader().getResourceAsStream("net/viralpatel/resources/config.properties"); try { configProp.load(in); } catch (IOException e) { e.printStackTrace(); } }
Code language: Java (java)
The folder structure of our example code will be: The full Java code for testing
package net.viralpatel.java; import java.io.IOException; import java.io.InputStream; import java.util.Properties; import java.util.ResourceBundle; public class LoadPropertiesExample { private Properties configProp = new Properties(); public static void main(String[] args) { LoadPropertiesExample sample = new LoadPropertiesExample(); sample.loadProps2(); sample.sayHello(); } public void loadProps1() { InputStream in = this.getClass().getResourceAsStream("/net/viralpatel/resources/config.properties"); try { configProp.load(in); } catch (IOException e) { e.printStackTrace(); } } public void loadProps2() { InputStream in = this.getClass().getClassLoader().getResourceAsStream("net/viralpatel/resources/config.properties"); try { configProp.load(in); } catch (IOException e) { e.printStackTrace(); } } public void sayHello() { System.out.println(configProp.getProperty("hello.world")); } }
Code language: Java (java)

Further Reading

Java ClassLoader API Java World – Smartly Loading Properties Files

View Comments

  • Asking the class itself for resources seems weird to me. Is there any way to get that by asking the System or by other API not connected to the class you are using it in?

  • Hi..
    To load the property file in Java I think, it is very easy to do it. It will come in the form of directory when you are downloading this files..
    In Java 6 updated version, every properties class have been existed, take help form there to fulfil the requirements....

  • Simple method to load properties file.

    Properties props = new Properties();
    props.load(new FileInputStream("config.properties"));
    String value = props.getProperty("prop1");
    System.out.println(value);
    System.out.println(props.entrySet());

  • Hi Viral,
    NIce post. HOw do store some modified properties to the file in the same package as you mentioned. I used FileOutputstream, but it creates a new properties file elsewhere..i want the same properties file to contain the modified values...i am goign berserk with this...

  • Thanks Dude
    Very good Post.
    I was struggling like anything.
    My problem was to load dataset file from resource folder (in DBUnit)
    return new FlatXmlDataSetBuilder().build(this.getClass().getResourceAsStream("/dataset.xml"));

    thanks again;

  • Could you tell me how to include the properties file path in my manifest? my properties file is in the resources folder. I need to include this in the class path of the JAR file, so that if any user wants they can modify the properties file externally and it will reflect in the JAR file

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