Problem Statement: I have few files in source directory. I have to move them to another destination directory. The source directory have *.txt files that needs to be moved to destination directory. The destination filename should be *.txt.backup. So how to accomplish the above task in Unix Shell Script? Well the solution is simple:
cd source/
for file in *.txt
do
mv "${file}" ../destination/"${file}.backup"
Code language: Arduino (arduino)
Run a loop for each txt file in source/ directory and call mv command with parameters. Does the above problem have a simpler solution than this?
for file in *.txt
will fail if ‘number of arguments to ls’ is more than its limit. For that
http://unstableme.blogspot.com/2009/02/handling-argument-list-too-long-bash.html
find . /source -name “*.txt” -exec mv {} ../destination/{}.backup ;\
we can use this command also..right
We can use this command also ..right